I am trying to destructure a tuple in a case statement and I am getting a warning that confuses me. It passes my test case, so it works, but the linter is giving me a warning and I’m not sure how to handle it. Am I doing a bad practice? I have a simplified scenario that demonstrates the warning below.

def test(x) do
  case x do
    tuple when is_tuple(tuple) ->
      {v1, v2} = tuple
      IO.puts(v1)
      IO.puts(v2)
  end
end

The warning is

incompatible types:
    tuple() !~ {var1, var2}
in expression:
    # [file path]
    {v1, v2} = x
where "x" was given the type tuple() in:
    # [file path]
    is_tuple(x)
where "x" was given the type {var1, var2} in:
    # [file path]
    {v1, v2} = x