iex(5)> for i <- 0..10, i > 0, do: IO.puts i
1
2
3
4
5
6
7
8
9
10
[:ok, :ok, :ok, :ok, :ok, :ok, :ok, :ok, :ok, :ok]
iex(6)> for i <- 0..0, i > 0, do: IO.puts i 
[]

Ranges work fine with 0.

Enum.each(0..x, fn i -> do_something(i) end)

If you mean the specific case of 0..0, it can be dealt with like this

Enum.each(0..x, fn
  0 -> :nothing
  _ -> do_something()
end)

It appeared that Range type in Elixir has step:

iex(1)> Map.from_struct(1..0)
%{first: 1, last: 0, step: -1}

So it’s possible to overcome the “do nothing” problem via this range creation syntax:

for _ <- 1..n//1, do: something()

This loop will call something() n times, and will NOT call it at all when n == 0

See Range — Elixir v1.13.4 for more examples

Right, I was just wondering if there was something that more directly replaced Enum.times that I missed. Thanks!