tcoopman
Is the multiline modifier for regexes on by default?
It looks like the m multiline modifier for regex is on by default?
iex(17)> Regex.match?(~r/^foo$/, "foo\n")
true
iex(18)> Regex.match?(~r/^foo$/m, "foo\n")
true
I would expect the first case to fail because the multiline modifier is disabled? I know I can use \z but that it is still not clear why the first regex matches.
Marked As Solved
NobbZ
The way elixir does it is consistent with how perl does.
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AlchemistCamp
It’s also worth pointing out that if you actually want to match across lines, you’ll need the “dotall” s modifier:
Regex.match?(~r/^bar$/s, some_multiline_string)
NobbZ
It becomes relevant when you have more than a single line. Single line mode wont try to match in subsequent lines, multi line mode does:
iex(1)> Regex.match?(~r/^bar$/, "foo\nbar\n")
false
iex(2)> Regex.match?(~r/^bar$/m, "foo\nbar\n")
true
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