No, it is not correct as Elixir’s structures and Erlang’s records are completely different entities. In your case you want to create record:

require Qlc

defmodule TestSchema do
  Record.defrecord(:foo, id: nil, field: nil)
end

:mnesia.start()

:mnesia.create_table(:test, [
  ram_copies: [node()],
  record_name: :foo,
  attributes: [:id, :field],
  type: :ordered_set
])

However I am not sure if it is possible to make Qlc “aware” of the :foo record in such case. Alternatively if you are using Erlang 21+ then you can do:

Qlc.q("[A || A <- mnesia:table('test'), map_get(field, A) == \"field 2\"]", [])

IIRC there was Elixir library that provided similar features as qlc but was implemented as Elixir macro, but I cannot recall it’s name right now.

Tried map_get/2 which don’t work, element/2 neither. It led me to a solution consisting in mnesia record pattern match.

An exemple below

require Qlc

defmodule TestSchema do
  defstruct id: nil, field: nil
end

:mnesia.start()

:mnesia.create_table(:test, [
  ram_copies: [node()],
  record_name: TestSchema,
  attributes: [:id, :field],
  type: :ordered_set
])

:mnesia.transaction fn ->
  :mnesia.write(:test, {TestSchema, 1, "field 2"}, :write)
end

query = Qlc.q("[[Id, Field] || {Schema, Id, Field} <- mnesia:table('test'), Id == 1]", [])
IO.inspect :mnesia.transaction fn ->
  Qlc.e(query)
end

# => {:atomic, [[1, "field 2"]]}