chrisdel101
Printing anonymous functions with ampersand
Is there anyway to print this &1?
I usually don’t know what the value is since was written by a generator, and doing IO.inspect(&1) gives an error.
Example Usage:
def create(conn, %{"employee" => %{"email" => email}}) do
if employee = Staff.get_employee_by_email(email) do
Staff.deliver_employee_confirmation_instructions(
employee,
&Routes.employee_confirmation_url(conn, :edit, &1)
)
end
Marked As Solved
sodapopcan
To expand a bit, where did you put the IO.inpect(&1)? I could be wrong, but something is telling me you put it outside the capture expression. &Routes.employee_confirmation_url(conn, :edit, IO.inspect(&1)) should do the trick.
Also Liked
codeanpeace
Did you include the capture operator aka the leading &?
In order to use &1, it needs to be &IO.inspect(&1).
Partials and function captures in Elixir | Erlang/Elixir Syntax: A Crash Course
Understanding the & (capture operator) in Elixir | Dockyard
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