LCMr_music
Help - a function that prints numbers in ascending order, until the provided parameter
Good Day All
How do I get to create or change this function to print out the Numbers in ascending order
if the provided variable is 4 the output should be
0
1
2
3
4
currently, I have created this one it prints in decending order, if input 4 output is :
4
3
2
1
0
here is the function:
def print(-1), do: :done
def print(n) do
puts("#{n} is #{[n]}")
print (n - 1)
end
Marked As Solved
Marcus
Welcome to the forum.
iex> fun = fn n -> 0..n |> Enum.each(fn i -> IO.puts(i) end) end
#Function<44.79398840/1 in :erl_eval.expr/5>
iex> fun.(4)
0
1
2
3
4
:ok
Also Liked
kokolegorille
Hello and welcome,
As mentionned using range is the easiest way.
0…n or n…0 in descending order.
But if You want to make it recursive, You need to pass some options, and take care of exit.
def print(-1, order: :desc), do: :done
def print(n, order: :asc, initial_value: n), do: :done
etc.
Please add ``` around your code to make it more readable 
Popular in Questions
Other popular topics
Latest on Elixir Forum
Sponsor Spotlight
Enabling companies to succeed by building software people love.
Categories:
Sub Categories:
Forums
Our Sponsors
Build Elixir applications with speed and confidence.
Supporting innovation across the BEAM ecosystem.
We build reliable cloud platforms for business-critical systems.
Catch errors, track performance, monitor hosts and more.
Practical resources that improve the lives of professional developers.
Producing high quality Elixir screencasts since 2017.
The deployment platform built for Elixir: PaaS ease, VPS control.
Courses that'll move you from confusion to "Aha, now I get it!"