edmundobiglia
How to remove ANSI escape sequences from a string?
What is the best way to strip ANSI escape sequences from a string?
Go from:
# Go from
"[\e[32m\"one\"\e[0m, \e[32m\"two\"\e[0m, \e[32m\"three\"\e[0m]"
# To
["one", "two", "three"]
Thanks a million!
Marked As Solved
ericgray
You can use a Regex
I just grabbed one online and used it. Not really good with Regexes so not sure how efficient this is.
defmodule MyAnsi do
@ansi_regex ~r/(\x9B|\x1B\[)[0-?]*[ -\/]*[@-~]/
@non_alpha_regex ~r/[^0-9a-zA-Z]/
def strip_ansi(ansi_string) when is_binary(ansi_string) do
Regex.replace(@ansi_regex, ansi_string, "")
|> String.split(",")
|> Enum.map(&Regex.replace(@non_alpha_regex, &1, ""))
end
end
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kip
Would produce a very expected output for all the people of the world that don’t use 7-bit ASCII scripts.
kip
axelson
Did you mean to say unexpected?
As a side-note I half (but probably less) implemented an ANSI parser, but ultimately changed the program output I was consuming to be most Lynn plain text. There’s quite a number of potential ANSI codes that you’d have to deal with for an accurate parser.
edmundobiglia
Thanks a million, works like a charm! 
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