theodore
Why do most functions pattern match structs on the left hand side?
Noob question. But I was just wondering, is there any advantage to pattern matching a struct on the left hand side vs right hand side?
For e.g
defmodule Test do
defstruct name: nil
def fun1(x = %Test{name: name}) do
IO.inspect(name)
end
def fun2(%Test{name: name} = x) do
IO.inspect(name)
end
end
It seems like both are equivalent, but the style of “struct on left hand side” is more common.
Here’s some other instances of what I mean
Most Liked
codeanpeace
Another reason why it’s likely more common is that it keeps things consistent.
When pattern matching outside a function head, the variable is always on the right of the = match operator since the other way around is for variable assignment
defmodule Test do
defstruct name: nil
def fun(x) do
%Test{name: name} = x
IO.inspect(name)
end
end
kip
You are right, they are functionally equivalent.
I tend to use the left hand side because when I’m scanning code, its the pattern match I want to focus on first. The binding is the second consideration - especially when there are multiple function heads matching on different constructs.
rvirding
Just to be different I prefer in Erlang to use the left hand side. To me it looks more like a pattern match which is what I am doing. ![]()
al2o3cr
+1 to this.
One other consideration: the x = %Test{name: name} shape looks similar to how other languages declare default arguments, versus the struct-on-the-left one which always means “pattern-match”.
adamu
This is the best reason I think ![]()
More specifically, the variables on the left side get bound (unless you use the pin operator to indicate you want to use an existing variable) based on the data on the right. In a function head, the variables on both sides are bound based on the argument to the function.







