laiboonh
Is there a nicer way to write this case statement
case Date.compare(date1, date2) do
:lt-> doA()
:gt -> doB()
:eq -> doA(); doB()
end
Thinking is there a way to write this more succinctly? Something like below but we know we cannot call a function for guard so the below does not compile
case Date.compare(date, get_changeover_date()) do
x when Enum.member?(x, [:lt, :eq]) -> doA()
x when Enum.member?(x, [:gt, :eq]) -> doB()
end
Marked As Solved
LostKobrakai
Given daA/0 and doB/0 seem to do sideeffects (return nothing of interest) you can do this:
result = Date.compare(date1, date2)
if result in [:lt, :eq], do: doA()
if result in [:gt, :eq], do: doB()
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moogle19
You can write:
case Date.compare(date, get_changeover_date()) do
x when x in [:lt, :eq] -> doA()
x when x in [:gt, :eq] -> doB()
end
but that is not the same as your example above, since only the first matching case will be executed.
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